Q.

Let f:ℝ→ℝ be a function defined by

f(x)={x2sin(πx2),if x≠00,if x=0

Then which of the following statements is TRUE               [2024]

1 f(x)=0 has infinitely many solutions in the interval [11010,∞).  
2 f(x)=0 has no solutions in the interval [1π,∞)  
3 The set of solutions of f(x)=0 in the interval (0,11010) is finite.  
4 f(x)=0 has more than 25 solutions in the interval (1π2,1π).  

Ans.

(4)

Given, f(x)={x2sin(πx2),if x≠00,if x=0

f(x)=0⇒sin(πx2)=0

⇒πx2=nπ⇒x2=1n⇒x=1n

(a) If x∈[11010,∞)

      1n∈[11010,∞)

       n∈(0,1010]

        n∈(0,(1010)2]

        Finite values of n are possible, so has finite solution.

(b) If x∈[1π,∞)⇒1n∈[1π,∞)

      n∈(0,π]⇒n∈(0,π2]⇒n=1,2,3,…,9

(c) If x∈(0,11010)⇒n∈(1010,∞)

       n is infinite

(d) If x∈(1π2,1π)⇒n∈(π,π2)

       n∈(π2,π4)⇒n∈(9.8,97.2,…)

       More than 25 solutions