Q.

Let f: be a function defined by

f(x)={x2sin(πx2),if x00,if x=0

Then which of the following statements is TRUE               [2024]

1 f(x)=0 has infinitely many solutions in the interval [11010,).  
2 f(x)=0 has no solutions in the interval [1π,)  
3 The set of solutions of f(x)=0 in the interval (0,11010) is finite.  
4 f(x)=0 has more than 25 solutions in the interval (1π2,1π).  

Ans.

(4)

Given, f(x)={x2sin(πx2),if x00,if x=0

f(x)=0sin(πx2)=0

πx2=nπx2=1nx=1n

(a) If x[11010,)

      1n[11010,)

       n(0,1010]

        n(0,(1010)2]

        Finite values of n are possible, so has finite solution.

(b) If x[1π,)1n[1π,)

      n(0,π]n(0,π2]n=1,2,3,,9

(c) If x(0,11010)n(1010,)

       n is infinite

(d) If x(1π2,1π)n(π,π2)

       n(π2,π4)n(9.8,97.2,)

       More than 25 solutions