Let [·] be the greatest integer function. If α=∫064(x1/3-[x1/3]) dx, then 1π∫0απ(sin2θsin6θ+cos6θ) dθ is equal to_______. [2026]
(36)
∵ ∫064x13 dx=34[x43]064=192
and
∫064[x1/3]dx=∫01[x1/3]dx+∫18[x1/3]dx+∫827[x1/3]dx+⋯+∫2764[x1/3]dx=156
So α=192-156=36
Now
E=1π∫036πsin2θsin6θ+cos6θdθ
=36π∫0πsin2θsin6θ+cos6θdθ
⇒E=36·2π∫0π/2sin2θsin6θ+cos6θdθ
Let J=∫0π/2sin2θsin6θ+cos6θdθ ...(1)
Applying King property,
J=∫0π/2cos2θsin6θ+cos6θdθ ...(2)
2J=∫0π/21sin6θ+cos6θdθ (add (1) & (2))
=∫0π/2sec6θtan6θ+1dθ
=∫0∞1+λ2λ4-λ2+1dλ
=∫0∞1+1λ2λ2-1+1λ2dλ
=π
⇒J=π2
⇒E=36·2π×J=36