Q.

Let [·] be the greatest integer function. If α=∫064(x1/3-[x1/3]) dx, then 1π∫0απ(sin2θsin6θ+cos6θ) dθ is equal to_______. [2026]


Ans.

(36)


∵ ∫064x13 dx=34[x43]064=192

and

∫064[x1/3]dx=∫01[x1/3]dx+∫18[x1/3]dx+∫827[x1/3]dx+⋯+∫2764[x1/3]dx=156

So α=192-156=36

Now

E=1π∫036πsin2θsin6θ+cos6θdθ

=36π∫0πsin2θsin6θ+cos6θdθ

⇒E=36·2π∫0π/2sin2θsin6θ+cos6θdθ

Let J=∫0π/2sin2θsin6θ+cos6θdθ    ...(1)

Applying King property,

J=∫0π/2cos2θsin6θ+cos6θdθ    ...(2)

Now

2J=∫0π/21sin6θ+cos6θdθ  (add (1) & (2))

=∫0π/2sec6θtan6θ+1dθ

=∫0∞1+λ2λ4-λ2+1dλ

=∫0∞1+1λ2λ2-1+1λ2dλ

=π

⇒J=π2

⇒E=36·2π×J=36