Q.

Let [·] be the greatest integer function. If α=064(x1/3-[x1/3]) dx, then 1π0απ(sin2θsin6θ+cos6θ)dθ is equal to_______. [2026]


Ans.

(36)


 064x13dx=34[x43]064=192

and

064[x1/3]dx=01[x1/3]dx+18[x1/3]dx+827[x1/3]dx++2764[x1/3]dx=156

So α=192-156=36

Now

E=1π036πsin2θsin6θ+cos6θdθ

=36π0πsin2θsin6θ+cos6θdθ

E=36·2π0π/2sin2θsin6θ+cos6θdθ

Let J=0π/2sin2θsin6θ+cos6θdθ    ...(1)

Applying King property,

J=0π/2cos2θsin6θ+cos6θdθ    ...(2)

Now

2J=0π/21sin6θ+cos6θdθ  (add (1) & (2))

=0π/2sec6θtan6θ+1dθ

=01+λ2λ4-λ2+1dλ

=01+1λ2λ2-1+1λ2dλ

=π

J=π2

E=36·2π×J=36