Q.

Let θ1,θ2,,θ10 be positive valued angles (in radian) such that θ1+θ2++θ10=2π. Define the complex numbers z1=eiθ1, zk=zk-1eiθk for k=2,3,,10,
where i=-1. Consider the statements P and Q given below:

P|z2-z1|+|z3-z2|++|z10-z9|+|z1-z10|2π

Q|z22-z12|+|z32-z22|++|z102-z92|+|z12-z102|4π                        [2021]

1 P is TRUE and Q is FALSE    
2 Q is TRUE and P is FALSE    
3 both P and Q are TRUE    
4 both P and Q are FALSE  

Ans.

(3)

Since, |z1|=|z2|==|z10|=1

θ2=arc(z1,z2)

|z2-z1|=length of line ABlength of arc AB

|z3-z2|=length of line BClength of arc BC

 Sum of length of these 10 lines  Sum of length of arcs (i.e. 2π)

                                                                   [ θ1+θ2+θ3++θ10=2π]

 P: |z2-z1|+|z3-z2|++|z1-z10|2π

P is true.

Now, |z22-z12|=|z2-z1||z2+z1|

We know that 

|z2+z1||z2|+|z1|2

 |z22-z12|+|z32-z22|++|z12-z102|2{|z2-z1|+|z3-z2|++|z1-z10|}2(2π)Q4π

Q is also true.