Q.

Let AP(a;d) denote the set of all the terms of an infinite arithmetic progression with first term a and common difference d>0. If AP(1;3)AP(2;5)AP(3;7)=AP(a;d), then a+d equals ______.                   [2019]


Ans.

(157)

AP (1,3):  1,4,7,10,13,

AP (2,5):  2,7,12,17,22,

AP (3,7):  3,10,17,24,31,

For AP (1,3)AP (2,5)AP (3,7) first term will be the minimum common value of a term.

 we need to find that minimum number which.

when divided by 7 leaves remainder 3(7m+3)

and when divided by 5 leaves remainder 2(5p+2)

and when divided by 3 leaves remainder 1(3q+1)

By hit and trial 52 is such number (7×7+3)

 first term 'a' of intersection AP = 52

Also common difference 'd' of intersection AP

=LCM(7,5,3)=105

 a+d=52+105=157