Q.

Let α and β be non-zero real numbers such that 2(cosβ-cosα)+cosαcosβ=1. Then which of the following is/are true         [2017]

1 tan(α2)+3tan(β2)=0  
2 3tan(α2)+tan(β2)=0  
3 tan(α2)-3tan(β2)=0  
4 3tan(α2)-tan(β2)=0  

Ans.

(1, 3)

If we consider tanα2=x and tanβ2=y, then

2(cosβ-cosα)+cosαcosβ=1

⇒2[1-y21+y2-1-x21+x2]=1-(1-x2)(1-y2)(1+x2)(1+y2)

⇒2[(1+x2)(1-y2)-(1-x2)(1+y2)]=(1+x2)(1+y2)-(1-x2)(1-y2)

⇒4(x2-y2)=2(x2+y2)

⇒x2=3y2⇒x=±3y

⇒tanα2±3tanβ2=0