Let α and β be non-zero real numbers such that 2(cosβ-cosα)+cosαcosβ=1. Then which of the following is/are true [2017]
(1, 3)
If we consider tanα2=x and tanβ2=y, then
2(cosβ-cosα)+cosαcosβ=1
⇒2[1-y21+y2-1-x21+x2]=1-(1-x2)(1-y2)(1+x2)(1+y2)
⇒2[(1+x2)(1-y2)-(1-x2)(1+y2)]=(1+x2)(1+y2)-(1-x2)(1-y2)
⇒4(x2-y2)=2(x2+y2)
⇒x2=3y2⇒x=±3y
⇒tanα2±3tanβ2=0