Let A be a 3×3 matrix such that |adj(adj(adjA))|=124. Then |A-1adjA| is equal to [2023]
(4)
Given, |adj(adj(adjA))|=124
⇒ |A|(n-1)3=124
At n=3, |A|8=124⇒|A|2=12⇒|A|=23
∴ |A-1adjA|=|A-1|·|adjA|=1|A|·|A|2=|A|=23