Q.

Let A,B,C be three sets of complex numbers as defined below

A={z:Im(z)1}

B={z:|z-2-i|=3}

C={z:Re((1-i)z)=2}

 

Q.   Let z be any point in ABC.  Then, |z+1-i|2+|z-5-i|2 lies between                   [2008]

1 25 and 29    
2 30 and 34    
3 35 and 39    
4 40 and 44  

Ans.

(3)

Given:  A={z:Im(z)1}={(x,y):y1}

Clearly A is the set of all points lying on or above the line y=1 in Cartesian plane.

B={z:|z-2-i|=3}={(x,y):(x-2)2+(y-1)2=9}

B is the set of all points lying on the boundary of the circle with centre (2, 1) and radius 3.

C={z:Re[(1-i)z]=2}={(x,y):x+y=2}

C is the set of all points lying on the straight line represented by x+y=2.

Graphically, the three sets are represented as shown below:

Since, z is a point of ABCz represents the point P

 |z+1-i|2+|z-5-i|2

|z-(-1+i)|2+|z-(5+i)|2

PQ2+PR2=QR2=62=36, which lies between 35 and 39

 (3) is correct option.