Q.

Let a,b,c be three non-zero real numbers such that the equation: 3acosx+2bsinx=c, x∈[-π2,π2], has two distinct real roots α and β with α+β=π3. Then, the value of ba is _______.                  [2018]


Ans.

(0.5)

Given: 3acosx+2bsinx=c

which has two roots α and β, such that α+β=π3

∴ 3acosα+2bsinα=c    ...(i)

and 3acosβ+2bsinβ=c    ...(ii)

On subtracting equation (ii) from (i),

3a(cosα-cosβ)+2b(sinα-sinβ)=0

⇒-3a·2sinα+β2sinα-β2+2b·2cosα+β2sinα-β2=0

⇒-23asinπ6+4bcosπ6=0     (∵sinα-β2≠0)

⇒-23a×12+4b32=0⇒ba=12=0.5