Let a,b,c be three non-zero real numbers such that the equation: 3acosx+2bsinx=c, x∈[-π2,π2], has two distinct real roots α and β with α+β=π3. Then, the value of ba is _______. [2018]
(0.5)
Given: 3acosx+2bsinx=c
which has two roots α and β, such that α+β=π3
∴ 3acosα+2bsinα=c ...(i)
and 3acosβ+2bsinβ=c ...(ii)
On subtracting equation (ii) from (i),
3a(cosα-cosβ)+2b(sinα-sinβ)=0
⇒-3a·2sinα+β2sinα-β2+2b·2cosα+β2sinα-β2=0
⇒-23asinπ6+4bcosπ6=0 (∵sinα-β2≠0)
⇒-23a×12+4b32=0⇒ba=12=0.5