Q.

Let a,b,c be the sides of a triangle where abc and λR. If the roots of the equation x2+2(a+b+c)x+3λ(ab+bc+ca)=0 are real, then        [2006]

1 λ<43  
2 λ>53  
3 λ(13,53)  
4 λ(43,53)  

Ans.

(1)

 a,b,c are sides of a triangle and abc

 |a-b|<|c|a2+b2-2ab<c2       (i)

Similarly,

b2+c2-2bc<a2    (ii),  c2+a2-2ca<b2    (iii)

On adding (i), (ii) and (iii) we get

a2+b2+c2<2(ab+bc+ca)

a2+b2+c2ab+bc+ca<2         (iv)

 Roots of the given equation are real

 (a+b+c)2-3λ(ab+bc+ca)0

a2+b2+c2ab+bc+ca3λ-2             (v)

From (iv) and (v), 3λ-2<2λ<43