Q.

Let a,b,c be the sides of a triangle where a≠b≠c and λ∈R. If the roots of the equation x2+2(a+b+c)x+3λ(ab+bc+ca)=0 are real, then        [2006]

1 λ<43  
2 λ>53  
3 λ∈(13,53)  
4 λ∈(43,53)  

Ans.

(1)

∵ a,b,c are sides of a triangle and a≠b≠c

∴ |a-b|<|c|⇒a2+b2-2ab<c2       ⋯(i)

Similarly,

b2+c2-2bc<a2    ⋯(ii),  c2+a2-2ca<b2    ⋯(iii)

On adding (i), (ii) and (iii) we get

a2+b2+c2<2(ab+bc+ca)

⇒a2+b2+c2ab+bc+ca<2         ⋯(iv)

∵ Roots of the given equation are real

∴ (a+b+c)2-3λ(ab+bc+ca)≥0

⇒a2+b2+c2ab+bc+ca≥3λ-2             ⋯(v)

From (iv) and (v), 3λ-2<2⇒λ<43