Q.

Let 75...57⏞r denote the (r+2) digit number where the first and the last digits are 7 and the remaining r digits are 5. Consider the sum S=77+757+7557+⋯+75...57⏞98. If S=75...57⏞99+mn, where m and n are natural numbers less than 3000, then the value of m+n is                [2023]


Ans.

(1219)

Given S=77+757+7557+⋯+75...57⏞98

10S=770+7570+⋯+75........570+75...570⏞98-9S=   77-13-13-⋯-13⏟98 times-75…570⏟98

9S=-77+13×98+75…57⏟99+13

S=75.....57⏞99+12109

⇒  m=1210, n=9 ⇒ m+n=1219.