Q.

Let 75...57r denote the (r+2) digit number where the first and the last digits are 7 and the remaining r digits are 5. Consider the sum S=77+757+7557++75...5798. If S=75...5799+mn, where m and n are natural numbers less than 3000, then the value of m+n is                [2023]


Ans.

(1219)

Given S=77+757+7557++75...5798

10S=770+7570++75........570+75...57098-9S=   77-13-13--1398 times-7557098

9S=-77+13×98+755799+13

S=75.....5799+12109

  m=1210, n=9  m+n=1219.