Q.

The key feature of Bohr's theory of the spectrum of the hydrogen atom is the quantization of angular momentum when an electron revolves around a proton. We will extend this to a general rotational motion to find the quantized rotational energy of a diatomic molecule assuming it to be rigid. The rule to be applied is Bohr's quantization condition.         [2010]

Q.    It is found that the excitation frequency from ground to the first excited state of rotation for the CO molecule is close to 4π×1011 Hz. Then the moment of inertia of the CO molecule about its center of mass is close to    (Take h=2π×10-34J s)

1 2.76×10-46kg m2  
2 1.87×10-46kg m2  
3 4.67×10-47kg m2  
4 1.17×10-47kg m2  

Ans.

(2)

Rotational kinetic energy K.E.rot=12Iω2=12I(LI)2             [∵L=Iω]

And according to Bohr's quantisation principle, L=nh2π

∴  K.E.rot=12L2I=12I×n2h24π2=n2[h28π2I]              ⋯(i)

From ground state (n=1) to first excited state (n=2),

Energy given = change in kinetic energy

hν=Kf-Ki=h28π2I(22-12)         [From Eq. (i)]

hν=3h28π2I⇒I=3h8π2ν=3×2π×10-348π2×4π×1011=316×10-45

I=1.87×10-46 kg m2