is the time required for the reaction to undergo 99.9% completion and is the time required for the reaction to undergo 50% completion. The relation between and for a first order reaction is . The value of is _______ (nearest integer).

Question

$t_{99.9}$ is the time required for the reaction to undergo 99.9% completion and $t_{50}$ is the time required for the reaction to undergo 50% completion. The relation between $t_{99.9}$ and $t_{50}$ for a first order reaction is $t_{99.9} = x t_{50}$ . The value of $x$ is _______ (nearest integer).

Smart Achievers · Accepted Answer

(10)

$t_{99.9} = \frac{2.303}{K} \log \frac{100}{0.1} = \frac{6.909}{K} = \frac{\frac{6.909}{0.69}}{t_{1 / 2}} = 10 t_{1 / 2}$

Solution

Ans.
(10)

$t_{99.9} = \frac{2.303}{K} \log \frac{100}{0.1} = \frac{6.909}{K} = \frac{\frac{6.909}{0.69}}{t_{1 / 2}} = 10 t_{1 / 2}$

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Solution

Q. t99.9 is the time required for the reaction to undergo 99.9% completion and t50 is the time required for the reaction to undergo 50% completion. The relation between t99.9 and t50 for a first order reaction is t99.9=xt50. The value of x is _______ (nearest integer).

Ans. (10) t99.9=2.303Klog1000.1=6.909K=6.9090.69t1/2=10t1/2

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Ans.
(10)

$t_{99.9} = \frac{2.303}{K} \log \frac{100}{0.1} = \frac{6.909}{K} = \frac{\frac{6.909}{0.69}}{t_{1 / 2}} = 10 t_{1 / 2}$