In the given figure ∆ABC is shown. DE is parallel to BC. If AD = 5 cm, DB = 2.5 cm and BC = 12 cm, then DE is equal to
(3)
AD=5 cm
DB=2.5 cm
BC=12 cm
DE∥BC
∆ABC~∆ADE
⇒ADAB=DEBC⇒57.5=DE12⇒DE=607.5=8 cm