Q.

In the given figure below, AD/AE = AC/BD and ∠1=∠2.. Show that Δ BAE~ΔCAD .


Ans.

In ∆ABC,  ∠1=∠2

∴ AB = BD                                                        ..............(i)

Given, ADAE=ACBD

Using equation (i), we get ADAE=ACAB           .............(ii)

In ΔBAE and ΔCAD, by equation (ii), ACAB=ADAE

and ∠A=∠A (common)

∴ ΔBAE ~ ΔCAD [By SAS similarity criterion]