• 072920 77839
  • info@smartachievers.in
Menu
Back
  • JEE ADVANCE
  • JEE MAIN
  • NEET
  • BITSAT
  • CBSE BOARD
  • UP BOARD
  • CUET
JEE ADVANCE
  • CLASS XI - XII
  • CRASH COURSE
CRASH COURSE
JEE MAIN
  • CLASS XI - XII
  • CRASH COURSE
CRASH COURSE
NEET
  • CLASS XI - XII
  • CRASH COURSE
BITSAT
  • CLASS XI - XII
CBSE BOARD
  • CLASS IX
  • CLASS X
  • CLASS XI
  • CLASS XII
  • CLASS VI
  • CLASS VII
  • CLASS VIII
UP BOARD
  • CLASS IX
  • CLASS X
  • CLASS XI
  • CLASS XII
CUET
  • CRASH COURSE
Courses


Solution


Q.

In the given figure below, AD/AE = AC/BD and ∠1=∠2.. Show that Δ BAE~ΔCAD .

Ans.

In ∆ABC,  ∠1=∠2

∴ AB = BD                                                        ..............(i)

Given, ADAE=ACBD

Using equation (i), we get ADAE=ACAB           .............(ii)

In ΔBAE and ΔCAD, by equation (ii), ACAB=ADAE

and ∠A=∠A (common)

∴ ΔBAE ~ ΔCAD [By SAS similarity criterion]