In the given figure, AP = 3 cm, AR = 4.5 cm, AQ = 6 cm, AB = 5 cm, AC = 10 cm. Find the length of AD
(7.5)
In ∆ABC, APAB=35 ....(i)
AQAC=610=35 ...(ii)
From (i) and (ii), we get APAB=AQAC⇒PQ∥BC
In ∆ABD,PR∥BD⇒APAB=ARAD⇒35=4.5AD⇒AD=7.5cm