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Solution


Q.

In the given figure, AB and CD are tangents to a circle centred at O. Is ∠BAC=∠DCA Justify your answer.

Ans.

Tangent to a circle from an external point are equal

RA = RC

So, ∠RAC=∠RCA

Let ∠RAC=∠RCA=x

We know that BAR and DCR are straight line.

∠BAC+∠CAR=180⁰

⇒∠BAC+x=180⁰

⇒∠BAC=180⁰–x

Similarly, ∠DCA=180⁰–x

So ∠BAC=∠DCA