In the given electromagnetic wave , intensity of the associated light beam is (in )

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Solution

Q.
In the given electromagnetic wave $E_{y} = 600 \sin (ω t - k x) V m^{- 1}$ , intensity of the associated light beam is (in $W / m^{2}$ )

(Given $ε_{0} = 9 \times 10^{- 12} C^{2} N^{- 1} m^{- 2}$ ) [2024]

1 729

2 243

3 972

4 486

Ans.
(4)

Intensity, $I = \frac{1}{2} ϵ_{0} E_{0}^{2} c \Rightarrow I = \frac{9}{2} \times 36 \times 3 = 486 W / m^{2}$

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