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Solution


Q.

In the given circuit, the current (I) through the battery will be             [2023]
1 1.5 A  
2 1 A  
3 2.5 A  
4 2 A  

Ans.

(1)

In the circuit D1 and D3 are forward biased and D2 is reverse biased.

∴  I=1020/3=10×320=32 A=1.5 A