Q.

In the given circuit, it is observed that the current I is independent of the value of the resistance R6. Then the resistance values must satisfy                [2001]

1 R1R2R5=R3R4R6  
2 1R5+1R6=1R1+R2+1R3+R4  
3 R1R4=R2R3  
4 R1R3=R2R4=R5R6  

Ans.

(3)

As the current I is independent of R6, it follows that the resistances R1, R2, R3, R4 and R6 must form a balanced Wheatstone bridge.

∴  R1R4=R2R3