In the given circuit if the internal resistance of the batteries are negligible

Question

In the given circuit if the internal resistance of the batteries are negligible, then for what value of resistance R (in $Ω$ ) will the thermal power generated in it be maximum.

Smart Achievers · Accepted Answer

(2)

Given circuit can be simplified as dotted part can be replaced as

$P = {(\frac{6}{2 + R})}^{2} R = \frac{36 R}{{(2 + R)}^{2}}$

$For P to be maximum, \frac{d P}{d R} = 0$

Solution

Q.
In the given circuit if the internal resistance of the batteries are negligible, then for what value of resistance R (in $Ω$ ) will the thermal power generated in it be maximum.

Ans.
(2)

Given circuit can be simplified as dotted part can be replaced as

$P = {(\frac{6}{2 + R})}^{2} R = \frac{36 R}{{(2 + R)}^{2}}$

$For P to be maximum, \frac{d P}{d R} = 0$

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Solution

Q. In the given circuit if the internal resistance of the batteries are negligible, then for what value of resistance R (in Ω) will the thermal power generated in it be maximum.

Ans. (2) Given circuit can be simplified as dotted part can be replaced as P=(62+R)2R=36R(2+R)2 For P to be maximum, dPdR=0

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Q.
In the given circuit if the internal resistance of the batteries are negligible, then for what value of resistance R (in $Ω$ ) will the thermal power generated in it be maximum.

Ans.
(2)

Given circuit can be simplified as dotted part can be replaced as

$P = {(\frac{6}{2 + R})}^{2} R = \frac{36 R}{{(2 + R)}^{2}}$

$For P to be maximum, \frac{d P}{d R} = 0$