In the given circuit, charge on the capacitor changes as is varied from to . as a function of is given properly by: (figures are drawn schematically and are not to scale) [2015]

Question

In the given circuit, charge $Q_{2}$ on the $2 μ F$ capacitor changes as $C$ is varied from $1 μ F$ to $3 μ F$ . $Q_{2}$ as a function of $' C'$ is given properly by: (figures are drawn schematically and are not to scale) [2015]

Smart Achievers · Accepted Answer

(4)

From figure, $2 μ F$

$Q = E (\frac{C \times 3}{C + 3})$

Therefore graph $d$ correctly depicts.

$∴$ $Q_{2} = \frac{2}{3} (\frac{3 C E}{C + 3}) = \frac{2 C E}{C + 3}$

Solution

Q.
In the given circuit, charge $Q_{2}$ on the $2 μ F$ capacitor changes as $C$ is varied from $1 μ F$ to $3 μ F$ . $Q_{2}$ as a function of $' C'$ is given properly by: (figures are drawn schematically and are not to scale) [2015]

1

2

3

4

Ans.
(4)

From figure, $Q_{2} = \frac{2}{2 + 1} Q = \frac{2}{3} Q$

$Q = E (\frac{C \times 3}{C + 3})$

Therefore graph $d$ correctly depicts.

$∴$ $Q_{2} = \frac{2}{3} (\frac{3 C E}{C + 3}) = \frac{2 C E}{C + 3}$

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Solution

Q. In the given circuit, charge Q2 on the 2 μF capacitor changes as C is varied from 1 μF to 3 μF. Q2 as a function of 'C' is given properly by: (figures are drawn schematically and are not to scale) [2015]

1

2

3

4

Ans. (4) From figure, Q2=22+1Q=23Q Q=E(C×3C+3) Therefore graph d correctly depicts. ∴ Q2=23(3CEC+3)=2CEC+3

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Q.
In the given circuit, charge $Q_{2}$ on the $2 μ F$ capacitor changes as $C$ is varied from $1 μ F$ to $3 μ F$ . $Q_{2}$ as a function of $' C'$ is given properly by: (figures are drawn schematically and are not to scale) [2015]

Ans.
(4)

From figure, $Q_{2} = \frac{2}{2 + 1} Q = \frac{2}{3} Q$

$Q = E (\frac{C \times 3}{C + 3})$

Therefore graph $d$ correctly depicts.

$∴$ $Q_{2} = \frac{2}{3} (\frac{3 C E}{C + 3}) = \frac{2 C E}{C + 3}$