In the given circuit, a charge of is given to the upper plate of the capacitor. Then in the steady state, the charge on the upper plate of the capacitor is [2012]

Question

In the given circuit, a charge of $+ 80 μ C$ is given to the upper plate of the $4 μ F$ capacitor. Then in the steady state, the charge on the upper plate of the $3 μ F$ capacitor is [2012]

Smart Achievers · Accepted Answer

(3)

The total charge on plate A will be $80 μ C .$

The $2 μ F$ and $3 μ F$ capacitors are in parallel. Therefore,

$C_{eq} = 2 + 3 = 5 μ F$

Charge on the capacitor of capacitance $3 μ F$ is

$q = \frac{3}{5} \times 80 = 48 μ C$

Solution

Q.
In the given circuit, a charge of $+ 80 μ C$ is given to the upper plate of the $4 μ F$ capacitor. Then in the steady state, the charge on the upper plate of the $3 μ F$ capacitor is [2012]

1 $+ 32 μ C$

2 $+ 40 μ C$

3 $+ 48 μ C$

4 $+ 80 μ C$

Ans.
(3)

The total charge on plate A will be $80 μ C .$

The $2 μ F$ and $3 μ F$ capacitors are in parallel. Therefore,

$C_{eq} = 2 + 3 = 5 μ F$

Charge on the capacitor of capacitance $3 μ F$ is

$q = \frac{3}{5} \times 80 = 48 μ C$

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Solution

Q. In the given circuit, a charge of +80 μC is given to the upper plate of the 4 μF capacitor. Then in the steady state, the charge on the upper plate of the 3 μF capacitor is [2012]

1 +32 μC

2 +40 μC

3 +48 μC

4 +80 μC

Ans. (3) The total charge on plate A will be 80 μC. The 2 μF and 3 μF capacitors are in parallel. Therefore, Ceq=2+3=5 μF Charge on the capacitor of capacitance 3 μF is q=35×80=48 μC