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Solution


Q.

In the above diagram, a strong bar magnet is moving towards solenoid-2 from solenoid-1. The direction of induced current in solenoid-1 and that in solenoid-2, respectively, are through the directions              [2024]
1 AB and DC  
2 BA and CD  
3 AB and CD  
4 BA and DC  

Ans.

(1)

In the given figure, north pole of the magnet is moving away from the solenoid AB. So the direction of current at end B is in such a way that it will oppose the movement of the bar magnet towards solenoid 2. Hence, end B will act as south pole and direction of current will be in clockwise direction i.e., A to B.

Now, south pole of the bar magnet is approaching solenoid-2, hence, it will oppose the movement of the magnet, therefore, C will act as South pole and induced current will be in anti-clockwise direction i.e., D to C.