In the above conversion of compound (X) to product (Y), the sequence of reagents to be used will be: [2023]

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Solution

Q.

In the above conversion of compound (X) to product (Y), the sequence of reagents to be used will be: [2023]

1 $(i) Fe, H^{+} (ii) {Br}_{2} (aq) (iii) {HNO}_{2} (iv) CuBr$

2 $(i) Fe, H^{+} (ii) {Br}_{2} (aq) (iii) {HNO}_{2} (iv) H_{3} {PO}_{2}$

3 $(i) {Br}_{2}, Fe (ii) Fe, H^{+} (iii) {LiAlH}_{4}$

4 $(i) {Br}_{2} (aq) (ii) {LiAlH}_{4} (iii) H_{3} O^{+}$

Ans.
(2)

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Solution

Q. In the above conversion of compound (X) to product (Y), the sequence of reagents to be used will be: [2023]

1 (i)Fe,H+ (ii)Br2(aq) (iii)HNO2 (iv)CuBr

2 (i)Fe,H+ (ii)Br2(aq) (iii)HNO2 (iv)H3PO2

3 (i)Br2,Fe (ii)Fe,H+ (iii)LiAlH4

4 (i)Br2(aq) (ii)LiAlH4 (iii)H3O+

Ans. (2)

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Q.

In the above conversion of compound (X) to product (Y), the sequence of reagents to be used will be: [2023]

1 $(i) Fe, H^{+} (ii) {Br}_{2} (aq) (iii) {HNO}_{2} (iv) CuBr$

2 $(i) Fe, H^{+} (ii) {Br}_{2} (aq) (iii) {HNO}_{2} (iv) H_{3} {PO}_{2}$

3 $(i) {Br}_{2}, Fe (ii) Fe, H^{+} (iii) {LiAlH}_{4}$

4 $(i) {Br}_{2} (aq) (ii) {LiAlH}_{4} (iii) H_{3} O^{+}$

Ans.
(2)