In Lassaigne's extract of an organic compound, both nitrogen and sulphur are present, which gives blood red colour with due to the formation of [2023]

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Q.
In Lassaigne's extract of an organic compound, both nitrogen and sulphur are present, which gives blood red colour with ${Fe}^{3 +}$ due to the formation of [2023]

1 ${[F e {(C N)}_{5} N O S]}^{4 -}$

2 ${[F e (S C N)]}^{2 +}$

3 $F e_{4} {[F e {(C N)}_{6}]}_{3} \cdot x H_{2} O$

4 NaSCN

Ans.
(2)

In case, nitrogen and sulphur both are present in an organic compound, sodium thiocyanate is formed. It gives blood red colour and no Prussian blue since there are no free cyanide.

$Na + C + N + S ⟶ NaSCN$

${Fe}^{3 +} + {SCN}^{-} ⟶ \underset{Blood red}{{[Fe (SCN)]}^{2 +}}$

Solution

Q.
In Lassaigne's extract of an organic compound, both nitrogen and sulphur are present, which gives blood red colour with ${Fe}^{3 +}$ due to the formation of [2023]

1 ${[F e {(C N)}_{5} N O S]}^{4 -}$

2 ${[F e (S C N)]}^{2 +}$

3 $F e_{4} {[F e {(C N)}_{6}]}_{3} \cdot x H_{2} O$

4 NaSCN

Ans.
(2)

In case, nitrogen and sulphur both are present in an organic compound, sodium thiocyanate is formed. It gives blood red colour and no Prussian blue since there are no free cyanide.

$Na + C + N + S ⟶ NaSCN$

${Fe}^{3 +} + {SCN}^{-} ⟶ \underset{Blood red}{{[Fe (SCN)]}^{2 +}}$

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Solution

Q. In Lassaigne's extract of an organic compound, both nitrogen and sulphur are present, which gives blood red colour with Fe3+ due to the formation of [2023]

1 [Fe(CN)5NOS]4-

2 [Fe(SCN)]2+

3 Fe4[Fe(CN)6]3·xH2O

4 NaSCN

Ans. (2) In case, nitrogen and sulphur both are present in an organic compound, sodium thiocyanate is formed. It gives blood red colour and no Prussian blue since there are no free cyanide. Na+C+N+S⟶NaSCN Fe3++SCN-⟶[Fe(SCN)]2+Blood red

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Q.
In Lassaigne's extract of an organic compound, both nitrogen and sulphur are present, which gives blood red colour with ${Fe}^{3 +}$ due to the formation of [2023]

1 ${[F e {(C N)}_{5} N O S]}^{4 -}$

2 ${[F e (S C N)]}^{2 +}$

3 $F e_{4} {[F e {(C N)}_{6}]}_{3} \cdot x H_{2} O$

Ans.
(2)

In case, nitrogen and sulphur both are present in an organic compound, sodium thiocyanate is formed. It gives blood red colour and no Prussian blue since there are no free cyanide.

$Na + C + N + S ⟶ NaSCN$

${Fe}^{3 +} + {SCN}^{-} ⟶ \underset{Blood red}{{[Fe (SCN)]}^{2 +}}$