In Fig, in trapezium ABCD if AB ∥ CD, then the value of x is
(3)
Since ABCD is a trapezium with AB ? CD and diagonals intersect at O
AO/OC = OB/OD ⇒ 2/5 = (x - 2)/(2x + 5)
= 2(2x + 5) = 5(x - 2)
= 4x + 10 = 5x - 10 ⇒ x = 20
Option (c) is correct.