In an ideal transformer, the turns ratio is . The ratio is equal to (the symbols carry their usual meaning) [2024]

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Solution

Q.
In an ideal transformer, the turns ratio is $\frac{N_{p}}{N_{s}} = \frac{1}{2}$ . The ratio $V_{s} : V_{p}$ is equal to (the symbols carry their usual meaning) [2024]

1 1 : 2

2 2 : 1

3 1 : 1

4 1 : 4

Ans.
(2)

Here, $\frac{N_{p}}{N_{s}} = \frac{1}{2}$

For ideal transformer, $\frac{N_{p}}{N_{s}} = \frac{V_{p}}{V_{s}}$

$\Rightarrow \frac{1}{2} = \frac{V_{p}}{V_{s}} \Rightarrow \frac{V_{s}}{V_{p}} = \frac{2}{1}$

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