Q.

In an examination of Mathematics paper, there are 20 questions of equal marks and the question paper is divided into three sections: A, B, and C. A student is required to attempt total 15 questions taking at least 4 questions from each section. If section A has 8 questions, section B has 6 questions and section C has 6 questions, then the total number of ways a student can select 15 questions is ______.         [2024]


Ans.

(11376)

A            B          C             Number of ways

5            6           4             C58×C66×C46=56×1×15=840

6            5           4             C68×C56×C46=28×6×15=2520

6            4           5             C68×C46×C56=28×15×6=2520

5            5           5             C58×C56×C56=56×6×6=2016

4            6           5             C48×C66×C56=70×1×6=420

4            5           6             C48×C56×C66=70×6×1=420

5            4           6            C58×C46×C66=56×15×1=840

7         4            4            C78×C46×C46=8×15×15=1800

    Required number of ways = 840 + 2520 + 2520 + 2016 + 420 + 420 + 840 = 11376