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Solution


Q.

In △ABC, PQ ∥ BC. If PB = 6 cm, AP = 4 cm, AQ = 8 cm, the length of AC is:
1 12 cm   
2 20 cm   
3 6 cm   
4 14 cm  

Ans.

(2)

In △ABC, we have PQ ∥ BCAP/PB = AQ/QC = 4/6 = 8/QC⇒ 2/3 = 8/QC ⇒ QC = 12 cm∴ AC = AQ + QC = 8 + 12 = 20 cm