In a Young’s double slits experiment, the ratio of amplitude of light coming from slits is 2 : 1. The ratio of the maximum to minimum intensity in the interference pattern is [2023]

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Solution

Q.
In a Young’s double slits experiment, the ratio of amplitude of light coming from slits is 2 : 1. The ratio of the maximum to minimum intensity in the interference pattern is [2023]

1 9 : 4

2 9 : 1

3 2 : 1

4 25 : 9

Ans.
(2)

$Given that \frac{A_{1}}{A_{2}} = \frac{2}{1}$

$\frac{I_{\max}}{I_{\min}} = {(\frac{A_{1} + A_{2}}{A_{1} - A_{2}})}^{2} = \frac{9}{1} = 9 : 1$

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