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Solution


Q.

In a single throw of two dice, the probability of getting 12 as a product of two numbers obtained is:
1 1/9  
2 2/9  
3 4/9  
4 5/9  

Ans.

(1)

When two dice are thrown together, the possible outcomes are:

(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6),
(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6),
(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6),
(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6),
(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6),
(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6).

Therefore, the total number of possible outcomes = n(S)=36

Now, the outcomes favourable to event E ‘getting 12 as the product of two numbers obtained’ are
(2, 6), (3, 4), (4, 3), (6, 2).

So, the number of favourable outcomes = n(E)=4

Therefore, the probability of getting 12 as a product of two numbers obtained

P(E)=n(E)n(S)=436=19