In a plane EM wave, the electric field oscillates sinusoidally at a frequency of and an amplitude of . The total average energy density of the electromagnetic field of the wave is

STUDY MATERIALS
COURSES
MORE
SUCCESS STORY
ADMISSION
STORE

Back

JEE ADVANCE

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

JEE MAIN

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

NEET

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

BITSAT

CLASS XI - XII

CLASS XI - XII

CBSE BOARD

CLASS IX

CLASS X

CLASS XI

CLASS XII

CLASS VI

CLASS VII

CLASS VIII

UP BOARD

CLASS IX
CLASS X
CLASS XI
CLASS XII

CLASS IX

CLASS X

CLASS XI

CLASS XII

CUET

CRASH COURSE

CRASH COURSE

Courses

CLASSROOM COURSES
ONLINE COURSES

ONLINE COURSES

Q.
In a plane EM wave, the electric field oscillates sinusoidally at a frequency of $5 \times 10^{10} H z$ and an amplitude of $50 V m^{- 1}$ . The total average energy density of the electromagnetic field of the wave is [Use $ε_{0} = 8.85 \times 10^{- 12} C^{2} / N m^{2}$ ] [2024]

Solution

Q.
In a plane EM wave, the electric field oscillates sinusoidally at a frequency of $5 \times 10^{10} H z$ and an amplitude of $50 V m^{- 1}$ . The total average energy density of the electromagnetic field of the wave is [Use $ε_{0} = 8.85 \times 10^{- 12} C^{2} / N m^{2}$ ] [2024]

1 $1.106 \times 10^{- 8} J m^{- 3}$

2 $2.212 \times 10^{- 10} J m^{- 3}$

3 $4.425 \times 10^{- 8} J m^{- 3}$

4 $2.212 \times 10^{- 8} J m^{- 3}$

Ans.
(1)

$U_{E} = \frac{1}{2} ϵ_{0} E^{2}$

$U_{E} = \frac{1}{2} \times 8.85 \times 10^{- 12} \times {(50)}^{2} = 1.106 \times 10^{- 8} J / m^{3}$

Want Us to Email you About Special Offers & Updates?

Solution

Q. In a plane EM wave, the electric field oscillates sinusoidally at a frequency of 5×1010Hz and an amplitude of 50Vm-1. The total average energy density of the electromagnetic field of the wave is [Use ε0=8.85×10-12C2/Nm2] [2024]

1 1.106×10-8Jm-3

2 2.212×10-10Jm-3

3 4.425×10-8Jm-3

4 2.212×10-8Jm-3

Ans. (1) UE=12ϵ0E2 UE=12×8.85×10-12×(50)2=1.106×10-8J/m3

Want Us to Email you About Special Offers & Updates?

Q.
In a plane EM wave, the electric field oscillates sinusoidally at a frequency of $5 \times 10^{10} H z$ and an amplitude of $50 V m^{- 1}$ . The total average energy density of the electromagnetic field of the wave is [Use $ε_{0} = 8.85 \times 10^{- 12} C^{2} / N m^{2}$ ] [2024]

1 $1.106 \times 10^{- 8} J m^{- 3}$

2 $2.212 \times 10^{- 10} J m^{- 3}$

3 $4.425 \times 10^{- 8} J m^{- 3}$

4 $2.212 \times 10^{- 8} J m^{- 3}$

Ans.
(1)

$U_{E} = \frac{1}{2} ϵ_{0} E^{2}$

$U_{E} = \frac{1}{2} \times 8.85 \times 10^{- 12} \times {(50)}^{2} = 1.106 \times 10^{- 8} J / m^{3}$