In a given process on an ideal gas, d W = 0 and d Q 0 . Then for the gas [2001]

Question

In a given process on an ideal gas, $d W = 0$ and $d Q < 0$ . Then for the gas [2001]

Smart Achievers · Accepted Answer

(1)

$From the first law of thermodynamics$

$d Q = d U + d W$

Here $d W = 0 (given)$

$∴$ $d Q = d U$

Now since $d Q < 0 (given)$

i.e., $d Q$ is negative so $d U$ decreases.

Internal energy $' U'$ decreases when temperature $T$ decreases.

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