In a first order decomposition reaction, the time taken for the decomposition of reactant to one fourth and one eighth of its initial concentration are and (s), respectively. The ratio will: [2025]

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Solution

Q.
In a first order decomposition reaction, the time taken for the decomposition of reactant to one fourth and one eighth of its initial concentration are $t_{1}$ and $t_{2}$ (s), respectively. The ratio $t_{1} / t_{2}$ will: [2025]

1 $\frac{4}{3}$

2 $\frac{3}{2}$

3 $\frac{3}{4}$

4 $\frac{2}{3}$

Ans.
(4)

$\frac{t_{1}}{t_{2}} = \frac{2 t_{1 / 2}}{3 t_{1 / 2}} = \frac{2}{3}$

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