In a class of 60 students, 25 students play cricket and 20 students play tennis and 10 students play both the games, then the number of students who play neither is

Question

Smart Achievers · Accepted Answer

(3)

Total number of students, $(N) = 60$

Let $n (C)$ be the number of students who play cricket and $n (T)$ be the number of students who play tennis.

$∴$ $n (C) = 25, n (T) = 20, n (C \cap T) = 10$

$So, n (C \cup T) = n (C) + n (T) - n (T \cap C) = 25 + 20 - 10 = 35$

Now, number of students who play neither game

$= n (C \cup T)' = N - n (C \cup T) = 60 - 35 = 25$

Solution

Q.
In a class of 60 students, 25 students play cricket and 20 students play tennis and 10 students play both the games, then the number of students who play neither is

1 45

2 0

3 25

4 35

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