In 9th term of the series 1 + 5 + 13 + 29 + ...... is given by
(4)
1+5+13+29+⋯
First difference 4, 8, 16,…∈G.P. ∴ r=2
∴ tn=a+br n-1=a+b(2)n-1
∴ n=1, n=2
we get a+b=1 and a+2b=5
a=-3, b=4
∴ tn=a+br n-1=4(2)n-1-3
∴ t9=4·28-3=1024-3=1021