If 2sin(A+B)=3 and cos(A-B)=1, then find the measures of angles A and B. 0≤A,B,(A+B)≤90°.
(30o)
2sin(A+B)=3⇒sin(A+B)=32=sin60°
⇒A+B=60° ....(i)
cos(A-B)=1=cos0°
⇒A-B=0° ....(ii)
Adding (i) and (ii), we get A=B=30°