Q.

If 2sin(A+B)=3 and cos(A-B)=1, then find the measures of angles A and B. 0≤A,B,(A+B)≤90°.


Ans.

(30o)

2sin(A+B)=3⇒sin(A+B)=32=sin60°

⇒A+B=60°   ....(i)

cos(A-B)=1=cos0°

⇒A-B=0°   ....(ii)

Adding (i) and (ii), we get A=B=30°