Q.

If two positive integers p and q are written as p=x2 y2  and  𝑞 = xy3, where x and y are prime numbers, then HCF(p, q) is:

1 xy  
2 xy2  
3 x3 y3  
4 -x2 y2  

Ans.

(2)

We have,

 p=x2y2q=xy3HCF(p,q)=xy2