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Solution


Q.

If the sum of zeros of the polynomial p(x) = 2x² – k√2x + 1 is √2, then value of k is:
1 √2           
2 2  
3 2√2        
4 1/2  

Ans.

(2)

Given polynomial is p(x) = 2x² – k√2x + 1.

Let α, β be its zeros then

α + β = –b/a = –(–k√2)/2 = k√2/2 = √2

[Here a = 2, b = –k√2, c = 1]

⇒ k√2 = 2√2 ⇒ k = 2