If the sum of zeroes of the polynomial is , then value of is :

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Solution

Q.
If the sum of zeroes of the polynomial $p (x) = 2 x^{2} - k \sqrt{2} x + 1$ is $\sqrt{2}$ , then value of $k$ is :

1 $\sqrt{2}$

2 $2$

3 $2 \sqrt{2}$

4 $1 / 2$

Ans.
(2)

Sum of zeroes $= \sqrt{2} = \frac{- (- k \sqrt{2})}{2} \Rightarrow k = 2$

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