If the sum of the first n terms of an AP is 3n² + n and its common difference is 6, then its first term is:
(4)
We have,Sₙ = 3n² + n⇒n/2(2a+(n"-"1)×6)=3n2+n⇒ a + 3n – 3 = 3n + 1⇒ a = 1 + 3⇒ a = 4