Q.

If the sum of the first n terms of an AP is 3n² + n and its common difference is 6, then its first term is:

1 2  
2 3  
3 1  
4 4  

Ans.

(4)

We have,S = 3n² + nn/2(2a+(n"-"1)×6)=3n2+n a + 3n  3 = 3n + 1 a = 1 + 3 a = 4