• 072920 77839
  • info@smartachievers.in
Menu
Back
  • JEE ADVANCE
  • JEE MAIN
  • NEET
  • BITSAT
  • CBSE BOARD
  • UP BOARD
  • CUET
  • Other Competitive Exams
JEE ADVANCE
  • CLASS XI - XII
  • CRASH COURSE
JEE MAIN
  • CLASS XI - XII
  • CRASH COURSE
CRASH COURSE
NEET
  • CLASS XI - XII
  • CRASH COURSE
BITSAT
  • CLASS XI - XII
CBSE BOARD
  • CLASS IX
  • CLASS X
  • CLASS XI
  • CLASS XII
  • CLASS VI
  • CLASS VII
  • CLASS VIII
UP BOARD
  • CLASS IX
  • CLASS X
  • CLASS XI
  • CLASS XII
CUET
  • CRASH COURSE
Other Competitive Exams
  • NDA
Courses


Solution


Q.

If the points (k, 3), (2, k), (-k, 3) are collinear, then the values of k are
1 2, 3  
2 1, 0  
3 1, 2  
4 0, 3  

Ans.

(4)

Points (k,3), (2,k), (-k,3) are collinear

So, k(k-3)+2(3-3)+(-k)(3-k)=0

∴  k2-3k-3k+k2=0⇒k(k-3)=0

∴  k=0, 3