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Solution


Q.

If sin(A + B) = 1 and cos(A – B) = 3/2, 0°<A+B≤90° and A>B, then find the measures of angles A and B.

Ans.

(60°, 30°)

sin(A+B)=1=sin90°, so A+B=90°           ....(i)

cos(A-B)=32=cos30°, so A-B=30°     ...(ii)

From (i) & (ii) ∠A=60° and ∠B=30°