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Solution


Q.

If sin (A + B) = 3/2 and sin (A – B) = 12, 0 ≤ A + B ≤ 90° and A > B, then find A and B.

Ans.

(A = 45°, B = 15°)

sin(A+B)=32=sin60°

⇒A+B=60°   ....(i)

sin(A-B)=12=sin30°

⇒A-B=30°   ...(ii)

Solving eq. (i) and (ii), A=45° and B=15°