Q.

If sin4x2+cos4x3=15, then                   [2009]

1 tan2x=23  
2 sin8x8+cos8x27=1125  
3 tan2x=13  
4 sin8x8+cos8x27=2125  

Ans.

(1, 2)

Given: 

sin4x2+cos4x3=153sin4x+2cos4x=65

sin4x+2[sin4x+cos4x]=65

sin4x+2[1-2sin2xcos2x]=65

sin4x+2-4sin2x(1-sin2x)=65

5sin4x-4sin2x+2-65=0

25sin4x-20sin2x+4=0

(5sin2x-2)2=0sin2x=25

cos2x=35  and  tan2x=23

Also sin8x8+cos8x27=2625+3625=5625=1125