If sin4x2+cos4x3=15, then [2009]
(1, 2)
Given:
sin4x2+cos4x3=15⇒3sin4x+2cos4x=65
⇒sin4x+2[sin4x+cos4x]=65
⇒sin4x+2[1-2sin2xcos2x]=65
⇒sin4x+2-4sin2x(1-sin2x)=65
⇒5sin4x-4sin2x+2-65=0
⇒25sin4x-20sin2x+4=0
⇒(5sin2x-2)2=0⇒sin2x=25
⇒cos2x=35 and tan2x=23
Also sin8x8+cos8x27=2625+3625=5625=1125