If R is a relation defined by aRb iff a≤b on N×N, then which of the following is correct
(1)
Now
limx→0α(1+x+x22!+x33!+⋯)+β(1-x+x22!-x33!+⋯)+γ(x-x33!+⋯)x3 [∵sinx≤x ∀x∈R]
Constant terms should be zero ⇒α+β=0
Coefficient of x should be zero ⇒α-β+γ=0
Coefficient of x2 should be zero limx→0x3(α3!-β3!-γ3!)+x4(α3!-β3!-γ3!)x3=23
⇒α2+β2=0, Now ⇒α6-β6-γ6=23
⇒α=1, β=-1, γ=-2