If r = 1 n ( tan 2 r - 1 cos 2 r ) = tan p n - tan q , then find the value of ( p + q )

STUDY MATERIALS
COURSES
MORE
SUCCESS STORY
ADMISSION
STORE

Back

JEE ADVANCE

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

JEE MAIN

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

NEET

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

BITSAT

CLASS XI - XII

CLASS XI - XII

CBSE BOARD

CLASS IX

CLASS X

CLASS XI

CLASS XII

CLASS VI

CLASS VII

CLASS VIII

UP BOARD

CLASS IX
CLASS X
CLASS XI
CLASS XII

CLASS IX

CLASS X

CLASS XI

CLASS XII

CUET

CRASH COURSE

CRASH COURSE

Other Competitive Exams

NDA

NDA

MATHS

Courses

Class Room Courses
Online Live Courses
Online Recorded Courses

ONLINE COURSES

More

Solution

Q.
$If \sum_{r = 1}^{n} (\frac{\tan 2^{r - 1}}{\cos 2^{r}}) = \tan p^{n} - \tan q, then find the value of (p + q)$

Ans.
(3)

$\sum_{r = 1}^{n} \frac{\sin (2^{r} - 2^{r - 1})}{\cos 2^{r} \cos 2^{r - 1}} = \sum_{r = 1}^{n} (\tan 2^{r} - \tan 2^{r - 1}) = \tan 2^{n} - \tan 1$

Want Us to Email you About Special Offers & Updates?