If P(6, 1) be the orthocentre of the triangle whose vertices are A(5,-2), B(8, 3) and C(h, k), then the point C lies on the circle:
(3)
Slope of AD=3, Slope of BC=-13, Equation of BC=3y+x-17=0
Slope of BE=1, Slope of AC=-1, Equation of AC is x+y-3=0, point C is (-4,7)