Q.

If P(6, 1) be the orthocentre of the triangle whose vertices are A(5,-2), B(8, 3) and C(h, k), then the point C lies on the circle:

1 x2+y2-61=0  
2 x2+y2-52=0  
3 x2+y2-65=0  
4 x2+y2-74=0  

Ans.

(3)

Slope of AD=3,        Slope of BC=-13,    Equation of BC=3y+x-17=0

Slope of BE=1,    Slope of AC=-1,        Equation of AC is x+y-3=0,    point C is (-4,7)