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Solution


Q.

If ‘p’ is a root of the quadratic equation x2−(p+q)x+k=0,  then the value of k is:
1 p  
2 q  
3 p + q   
4 pq  

Ans.

Since p is a root of the quadratic equation

x2−(p+q)x+k=0,
we have
p2−(p+q)p+k=0⇒p2−p2−pq+k=0⇒k=pq