If one root is square of the other root of the equation x2+px+q=0, then the relation between p and q is [2004]
(1)
x2+px+q=0
Let roots be α and α2, then
α+α2=-p, α·α2=q⇒α=q1/3
∴ (q)1/3+(q1/3)2=-p
On taking cube on both sides, we get
q+q2+3q(q1/3+q2/3)=-p3
⇒q+q2-3pq=-p3
⇒p3+q2-q(3p-1)=0